AeroLab Reading room

Physics / A2 level

Capacitance

Describe charge storage and the energy transferred while charging.

Learning objectives

The big idea

A capacitor stores separated charge on conductors. Capacitance is charge magnitude on one conductor divided by their potential difference; it depends on geometry and the dielectric.

Charging transfers energy to the electric field. During discharge through a fixed resistor, charge, current and voltage decay exponentially in the ideal model. The time constant RC is a time scale, not the time for a mathematically complete discharge.

1. Separated charge stores energy

Capacitance C = Q/V relates the charge magnitude on one plate to the potential difference between plates. The two plates of a typical initially neutral capacitor carry opposite charges; adding their signed charges does not give the Q used in this equation. Capacitance depends on geometry and dielectric properties. Increasing a source voltage changes stored charge without necessarily changing the capacitance of an ideal component.

2. Series and parallel networks follow different rules

Parallel capacitors share voltage and their charges add, so equivalent capacitances add. Series capacitors in a simple initially uncharged chain have equal charge magnitude, while their potential differences add; reciprocals of capacitance therefore add. Two identical 10 μF capacitors give 20 μF in parallel but 5 μF in series. Identify the connections before choosing a rule remembered from resistor networks.

3. Charging requires work

As charge builds, further charge separation requires increasing work against the electric field. Stored energy is ½QV = ½CV² = Q²/(2C). Doubling voltage at fixed capacitance quadruples stored energy. In the simple circuit charging an initially uncharged capacitor from a constant-voltage source through a resistor, the source transfers CV² and half remains stored; the other half is dissipated in the idealised resistive charging process.

4. Discharge has a characteristic time

For an ideal discharge through a fixed resistor, Q = Q₀e^(−t/RC); voltage and current magnitude also decay exponentially. After one time constant RC, about 37% of the original charge remains, not zero. Larger resistance or capacitance prolongs the discharge. A straight logarithmic charge–time graph can reveal the time constant, but real leakage, meter loading and component tolerances can change measured behaviour.

A method you can reuse

  1. Identify each capacitor’s connections and initial conditions.
  2. Find equivalent capacitance using the correct series or parallel rule.
  3. Distinguish stored charge from the signed net charge of both plates.
  4. Use the appropriate energy or exponential discharge relationship.
  5. Check prefixes and recognise RC as a time rather than a complete-discharge moment.
Why does a capacitor retain some charge after one time constant?

Exponential decay removes a fixed fraction over each equal time interval. One time constant leaves e⁻¹ of the initial charge; it does not remove a fixed total amount.

Equations and relationships

C=QVC=\frac QV

Capacitance in farads.

E=12CV2E=\frac12CV^2

Stored energy.

Q=Q0e−t/(RC)Q=Q_0e^{-t/(RC)}

Ideal discharge through resistance R.

Worked example

A 2.0 μF capacitor is charged to 10 V. How much energy is stored?

Follow the solution

E = ½ × 2.0 × 10⁻⁶ × 10² = 1.0 × 10⁻⁴ J = 100 μJ.

Investigate and explain

Compare simulated capacitors at two voltages. Do not handle high-voltage capacitors, which may remain charged.

Use plate geometry for capacitance and circuits for charging or discharge where the component controls permit. These models do not justify handling real high-voltage capacitors, which may retain dangerous energy.

Open the interactive investigation

Check your understanding

1. How do capacitances combine in parallel?

  1. Their reciprocals add to give total capacitance.
  2. The total is smaller than either capacitance.
  3. The capacitances add.
Check the answer and reasoning

The capacitances add.

Parallel capacitors share voltage and their charges add.

2. A 2.0 μF capacitor is charged to 10 V. How much energy is stored?

  1. 100 μJ
  2. 10 μJ
  3. 100 mJ
Check the answer and reasoning

100 μJ

E = ½ × 2.0 × 10⁻⁶ × 10² = 1.0 × 10⁻⁴ J = 100 μJ.

3. After one time constant, about what initial charge fraction remains in an ideal discharge?

  1. 0
  2. 0.37
  3. 0.63
Check the answer and reasoning

0.37

Q/Q₀ = e⁻¹ ≈ 0.37.